■原始根とガウス和(その25)

 分母が14の場合を考える.

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[1]正弦・余弦の和公式から

 sinπ/14+sin2π/14+・・・+sin13π/14=cotπ/28

 cosπ/14+cos3π/14+・・・+cos27π/14=0

[2]正弦・余弦の積公式から

 sinπ/14・sin2π/14・・・sin13π/14=14/2^13

 cosπ/14・cos3π/14・・・cos27π/14=−1/2^26

 sinπ/14・sin3π/14・・・sin13π/14=1/2^13

 cosπ/14・cos3π/14・・・cos13π/14=0

 sinπ/14・sin2π/14・・・sin6π/14=√14/2^13/2

 sinπ/14・sin3π/14・sin5π/14=1/8

 cosπ/14・cos2π/14・・・cos6π/14=√7/64

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