■バーゼル問題の解法(その3)

 sinx/x=(1−x^2/π^2)(1−x^2/4π^2)(1−x^2/9π^2)・・・

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[1](1−1/4)(1−1/9)(1−1/16)・・・

 sinx/x(1−x^2/π^2)=(1−x^2/4π^2)(1−x^2/9π^2)・・・

=−π^2/x(x+π)・(sinx−sinπ)/(x−π)

x→πのとき,(sinx−sinπ)/(x−π)→cosπ

(1−1/4)(1−1/9)(1−1/16)・・・=1/2

 あるいは

(1−1/4)(1−1/9)(1−1/16)・・・(1−1/n^2)

=(1・3/2・2)・(2・4/3・3)・(3・5)/(4・4)・・・(n−1)(n+1)/n^2

=(n+1)/2n→1/2

[2](1−4/9)(1−4/16)(1−4/25)・・・

 sinx/x(1−x^2/π^2)(1−x^2/4π^2)=(1−x^2/9π^2)・・・

=π^3/x(x+π)(x−π)(x+2π)・(sinx−sin2π)/(x−2π)

x→2πのとき,(sin2x−sin2π)/(x−π)→cos2π

(1−4/9)(1−4/16)(1−4/25)・・・=1/6

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