(その16)の続き.
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(1-x)^α=F(-α,β,β:x)
(1+x)^-α
=1//1+αx//1+(1-α)x//2+(1+α)x//3+(2-α)x//2+(2+α)x//5+(3-α)x//2+・・・
(1+x)^α+(1-x)^α=2F((1-α)/2,-α/2,1/2:x^2)
(1+x)^α-(1-x)^α=2αxF((1-α)/2,1-α/2,1+1/2:x^2)
{(1+x)^α-(1-x)^α}/{(1+x)^α+(1-x)^α}
=αx//1+(α^2-1)x^2//3+(α^2-4)x^2//5+(α^2-9)x^2//7+・・・
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