■xexp(x)=1(その12)
超越方程式(3exp(3))^(x+2)=exp(5){1+5/(3x+1)}^(x+2)を解く
===================================
(3)^(x+2)exp(3x+6)=exp(5){(3x+6)/(3x+1)}^(x+2)
((3x+1)/(x+2))^(x+2)exp(3x+6)=exp(5)
((3x+1)/(x+2))^(x+2)exp(3x+1)=1
この先が進まない
===================================