■xexp(x)=1(その12)

超越方程式(3exp(3))^(x+2)=exp(5){1+5/(3x+1)}^(x+2)を解く

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(3)^(x+2)exp(3x+6)=exp(5){(3x+6)/(3x+1)}^(x+2)

((3x+1)/(x+2))^(x+2)exp(3x+6)=exp(5)

((3x+1)/(x+2))^(x+2)exp(3x+1)=1

この先が進まない

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