■フルヴィッツ曲線(その61)
公転と自転の向きを逆方向にとると,フルヴィッツ曲線の運動族は
x=(n-2)acos(nβ+θ)+nacos((n−2)β−θ)−2Rsin(β+θ)+2acos((n−1)θ)
y=-(n-2)asin(nβ+θ)+nasin((n−2)β−θ)−2Rcos(β+θ)+2asin((n−1)θ)
m=n
cos(mθ+β)-cos(n-1)β=0
sin(mθ+nβ)/2sin(mθ-(n-2)β)/2=0
(mθ+nβ)/2=0,π、2π、3π、・・・
(mθ-(n-2)β)/2=0,π、2π、3π、・・・
m=n=4
x=2cos(4β+θ)+4cos(2β-θ)−16sin(β+θ)+2cos(3θ)
y=-2sin(4β+θ)+4sin(2β-θ)−16cos(β+θ)+2sin(3θ)
mθ+nβ=0,θ=-βを代入すると
x=2cos(3β)+4cos(3β)+2cos(3β)
y=-2sin(3β)+4sin(3β)−16-2sin(3β)=-16 (直線)
(mθ-(n-2)β)/2=0、β=2θを代入すると
x=2cos(9θ)+4cos(3θ)−16sin(3θ)+2cos(3θ)
y=-2sin(9θ)+4sin(3θ)−16cos(3θ)+2sin(3θ)
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公転と自転の向きを同じ方向にとると,フルヴィッツ曲線の運動族は
x=(n-2)acos(nβ-θ)+nacos((n−2)β+θ)−2Rsin(β-θ)+2acos((n−1)θ)
y=-(n-2)asin(nβ-θ)+nasin((n−2)β+θ)−2Rcos(β-θ)+2asin((n−1)θ)
m=n-2
cos(mθ+β)+cos(n-1)β=0
cos(mθ+nβ)/2cos(mθ-(n-2)β)/2=0
(mθ+nβ)/2=π/2、3π/2、5π/2、・・・
(mθ-(n-2)β)/2=π/2、3π/2、5π/2、・・・
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辺縁は円だろうか?
m=2,n=4
(mθ-(n-2)β)/2=π/2
(2θ-2β)=π
θ=π/2+β
x=2cos(4β-θ)+4cos(2β+θ)−16sin(β-θ)+2cos(3θ)
y=-2sin(4β-θ)+4sin(2β+θ)−16cos(β-θ)+2sin(3θ)
x=2cos(3β-π/2)+4cos(π/2+3β)−16sin(-π/2)+2cos(3π/2+3β)
y=-2sin(3β-π/2)+4sin(π/2+3β)−16cos(-π/2)+2sin(3π/2+3β)
x=2sin(3β)-4sin(3β)+16+sin(3β)
y=2cos(3β)+4cos(3β)-2cos(3β)
x=-sin(3β)+16
y=4cos(3β)
これは円ではない。
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