■ガウス和と有限テータ関数(その10)

m=13のとき、

k=1:2/13

k=2:8/13

k=3:18/13=5/13+1

k=4:32/13=6/13+2

k=5:50/13=11/13+3

k=6:72/13=7/13+5

k=7:98/13=7/13+7

k=8:128/13=11/13+9

k=9:162/13=6/13+12

k=10:200/13=5/13+15

k=11:242/13=8/13+18

k=12:288/13=2/13+22

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2cos(2π/13)-2cos(5π/13)+2cos(6π/13)-2cos(7π/13)+2cos(8π/13)-2cos(11π/13)

4cos(2π/13)-4cos(5π/13)+4cos(6π/13)=√13-1

2sin(2π/13)-2sin(5π/13)+2sin(6π/13)-2sin(7π/13)+2sin(8π/13)-2sin(11π/13)=0

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