■オイラーと無限級数(その4)
オイラーは
[1]Σ{1/(8n+1)+1/(8n+3)−1/(8n+5)−1/(8n+7)}=π/2√2 (ニュートン)
だけでなく,
[1]Σ{1/(6n+1)+1/(6n+3)−1/(6n+4)−1/(6n+5)}=2π/3√3
も求めている.
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