■タクシー数(その14)

(2m^2−4m−1)^2+2(−2m^2−2m+1)^2=3(2m^2+1)^2

 x+y=2m^2−4m−1

 x−y=2m^2+2m−1

 2x=4m^2−2m−2,x=2m^2−m−1=(m−1)(2m+1)

 2y=−6m,y=−3m

  x=1/6・{3A±(12B−3A^2)^1/2}

 6x=3A±(12B−3A^2)^1/2

 2x=A±(2m^2+1)

 2(2m^2−m−1)=2m^2−4m−1±(2m^2+1)

となり,一致しない.これが不一致の原因である.

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