■逆数ディオファントス方程式（その１）
(x2+y2+1)/xy=3 ←→ x=F2n-1, y=F2n+1
(x2+y2-1)/xy=3 ←→ x=F2n, y=F2n+2
(x2+y2-5)/xy=3 ←→ x=L2n-1, y=L2n+1
(x2+y2+5)/xy=3 ←→ x=L2n, y=L2n+2
(x2+y2+4)/xy=6 ←→ x=P2n-1, y=P2n+1
(x2+y2-4)/xy=6 ←→ x=P2n, y=P2n+2
(x2+y2-32)/xy=6 ←→ x=Q2n-1, y=Q2n+1
(x2+y2+32)/xy=6 ←→ x=Q2n, y=Q2n+2
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{x+y+xy(x+y)}{1/x+1/y+1/xy(x+y)} =(x+y)2+6 ←→ x=F2n-1, y=F2n+1
{x+y+xy(x+y)}{1/x+1/y+4/xy(x+y)} =(x+y)2+12 ←→ x=P2n-1, y=P2n+1
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