■オイラーと無限級数(その4)

 オイラーは

[1]Σ{1/(8n+1)+1/(8n+3)−1/(8n+5)−1/(8n+7)}=π/2√2  (ニュートン)

だけでなく,

[1]Σ{1/(6n+1)+1/(6n+3)−1/(6n+4)−1/(6n+5)}=2π/3√3

も求めている.

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