■葉序らせん(その113)

 B,A,Fが同じ円に載る方向を求めることができるだろうか?

  A(0,0,1/2)

  B(0,0,−1/2)

  F(2√6/9,4√3/9,5/6)

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[ca・cb・cc−sa・sc,−ca・cb・sc−sa・cc,ca・sb]

[sa・cb・cc+ca・sc,−sa・cb・sc+ca・cc,sa・sb]

[−sb・cc,sb・sc,cb]

A(ca・sb/2,sa・sb/2,cb/2)

B(−ca・sb/2,−sa・sb/2,−cb/2)

F(ca・cb・cc−sa・sc)2√6/9+(−ca・cb・sc−sa・cc)4√3/9+(ca・sb)5/6,

(sa・cb・cc+ca・sc)2√6/9+(−sa・cb・sc+ca・cc)4√3/9+(sa・sb)5/6,

(−sb・cc)2√6/9+(sb・sc)4√3/9+(cb)5/6)

中心をO(x,y)として,AO=BO=FOとなるOを求める.AB=AFも必要条件.

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