■基本単体の二面角(その77)

 E6~について

  c0=1,c1=2 → L=1

  c1=2,c2=3 → L=1/√3

  (ここで分岐)

  c2=3,c3=2 → L=1/√3

  c3=2,c4=1 → L=1

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  (0,0,0,0,0,0)

  (1,0,0,0,0,0)

  (1,1/√3,1/√3,0,0,0)

  (1,1/√3,1/√3,1,0,0)

  (1,1/√3,0,0,1/√3,0)

  (1,1/√3,0,0,1/√3,1)

となるのだろうか?

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