■n次元の立方体と直角三角錐(その155)

 正四面体系:f0=4,f1=6,f2=4で再計算してみて,正八面体系の場合と一致するものを選んでみる.

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[1](0,1,0)→f=(6,12,8)

  [0,0,1,0]

  [1,0,2,0]

  [2,1,0,1]

[2](0,0,1)→f=(4,6,4)

  [0,0,0,1]

  [1,0,1,0]

  [2,1,0,0]

[3](1,1,0)→f=(12,18,8)

  [0,0,2,0],[0,0,0,3]

  [1,0,3,0]

  [2,1,0,1]

[4](1,0,1)→f=(12,24,14)

  [0,0,2,0],[0,0,0,3]

  [1,0,4,0],[1,0,2,3],[1,0,0,6]

  [2,1,1,1]

[5](0,1,1)→f=(12,18,8)

  [0,0,2,0],[0,0,0,3]

  [1,0,3,0],[1,0,1,3]

  [2,1,0,1]

[6](1,1,1)→f=(24,36,14)

  [0,0,4,0],[0,0,2,3],[0,0,0,6]

  [1,0,6,0],[1,0,4,3],[1,0,2,6],[1,0,0,9]

  [2,1,1,1]

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